20+3x=5(x-10)+3

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Solution for 20+3x=5(x-10)+3 equation: 



20+3x=5(x-10)+3

We move all terms to the left:

20+3x-(5(x-10)+3)=0



We calculate terms in parentheses: -(5(x-10)+3), so:

5(x-10)+3

We multiply parentheses

5x-50+3

We add all the numbers together, and all the variables

5x-47

Back to the equation:

-(5x-47)



We get rid of parentheses

3x-5x+47+20=0

We add all the numbers together, and all the variables

-2x+67=0

We move all terms containing x to the left, all other terms to the right

-2x=-67

x=-67/-2

x=33+1/2

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