20+3y-1=12y-11-3y

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Solution for 20+3y-1=12y-11-3y equation: 



20+3y-1=12y-11-3y

We move all terms to the left:

20+3y-1-(12y-11-3y)=0

We add all the numbers together, and all the variables

3y-(9y-11)+20-1=0

We add all the numbers together, and all the variables

3y-(9y-11)+19=0

We get rid of parentheses

3y-9y+11+19=0

We add all the numbers together, and all the variables

-6y+30=0

We move all terms containing y to the left, all other terms to the right

-6y=-30

y=-30/-6

y=+5

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