20+3y-4=10y-9-2y

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Solution for 20+3y-4=10y-9-2y equation: 



20+3y-4=10y-9-2y

We move all terms to the left:

20+3y-4-(10y-9-2y)=0

We add all the numbers together, and all the variables

3y-(8y-9)+20-4=0

We add all the numbers together, and all the variables

3y-(8y-9)+16=0

We get rid of parentheses

3y-8y+9+16=0

We add all the numbers together, and all the variables

-5y+25=0

We move all terms containing y to the left, all other terms to the right

-5y=-25

y=-25/-5

y=+5

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