20+3y-4=10y-9-2y

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Solution for 20+3y-4=10y-9-2y equation:



20+3y-4=10y-9-2y
We move all terms to the left:
20+3y-4-(10y-9-2y)=0
We add all the numbers together, and all the variables
3y-(8y-9)+20-4=0
We add all the numbers together, and all the variables
3y-(8y-9)+16=0
We get rid of parentheses
3y-8y+9+16=0
We add all the numbers together, and all the variables
-5y+25=0
We move all terms containing y to the left, all other terms to the right
-5y=-25
y=-25/-5
y=+5

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