20+3y-6=13y-10-4y

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Solution for 20+3y-6=13y-10-4y equation: 



20+3y-6=13y-10-4y

We move all terms to the left:

20+3y-6-(13y-10-4y)=0

We add all the numbers together, and all the variables

3y-(9y-10)+20-6=0

We add all the numbers together, and all the variables

3y-(9y-10)+14=0

We get rid of parentheses

3y-9y+10+14=0

We add all the numbers together, and all the variables

-6y+24=0

We move all terms containing y to the left, all other terms to the right

-6y=-24

y=-24/-6

y=+4

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