20+4(3x-5)+2x=28

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Solution for 20+4(3x-5)+2x=28 equation: 



20+4(3x-5)+2x=28

We move all terms to the left:

20+4(3x-5)+2x-(28)=0

We add all the numbers together, and all the variables

2x+4(3x-5)-8=0

We multiply parentheses

2x+12x-20-8=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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