20+4m=8(1+m)

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Solution for 20+4m=8(1+m) equation: 



20+4m=8(1+m)

We move all terms to the left:

20+4m-(8(1+m))=0

We add all the numbers together, and all the variables

4m-(8(m+1))+20=0



We calculate terms in parentheses: -(8(m+1)), so:

8(m+1)

We multiply parentheses

8m+8

Back to the equation:

-(8m+8)



We get rid of parentheses

4m-8m-8+20=0

We add all the numbers together, and all the variables

-4m+12=0

We move all terms containing m to the left, all other terms to the right

-4m=-12

m=-12/-4

m=+3

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