20+4x=3(-x+2)-28

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Solution for 20+4x=3(-x+2)-28 equation: 



20+4x=3(-x+2)-28

We move all terms to the left:

20+4x-(3(-x+2)-28)=0

We add all the numbers together, and all the variables

4x-(3(-1x+2)-28)+20=0



We calculate terms in parentheses: -(3(-1x+2)-28), so:

3(-1x+2)-28

We multiply parentheses

-3x+6-28

We add all the numbers together, and all the variables

-3x-22

Back to the equation:

-(-3x-22)



We get rid of parentheses

4x+3x+22+20=0

We add all the numbers together, and all the variables

7x+42=0

We move all terms containing x to the left, all other terms to the right

7x=-42

x=-42/7

x=-6

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