20+4y-5=-6+2y+40

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Solution for 20+4y-5=-6+2y+40 equation: 



20+4y-5=-6+2y+40

We move all terms to the left:

20+4y-5-(-6+2y+40)=0

We add all the numbers together, and all the variables

4y-(2y+34)+20-5=0

We add all the numbers together, and all the variables

4y-(2y+34)+15=0

We get rid of parentheses

4y-2y-34+15=0

We add all the numbers together, and all the variables

2y-19=0

We move all terms containing y to the left, all other terms to the right

2y=19

y=19/2

y=9+1/2

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