20+5(1-x)=2x-3x(x-2)

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Solution for 20+5(1-x)=2x-3x(x-2) equation: 



20+5(1-x)=2x-3x(x-2)

We move all terms to the left:

20+5(1-x)-(2x-3x(x-2))=0

We add all the numbers together, and all the variables

5(-1x+1)-(2x-3x(x-2))+20=0

We multiply parentheses

-5x-(2x-3x(x-2))+5+20=0



We calculate terms in parentheses: -(2x-3x(x-2)), so:

2x-3x(x-2)

We multiply parentheses

-3x^2+2x+6x

We add all the numbers together, and all the variables

-3x^2+8x

Back to the equation:

-(-3x^2+8x)



We add all the numbers together, and all the variables

-(-3x^2+8x)-5x+25=0

We get rid of parentheses

3x^2-8x-5x+25=0

We add all the numbers together, and all the variables

3x^2-13x+25=0

a = 3; b = -13; c = +25;
Δ = b2-4ac
Δ = -132-4·3·25
Δ = -131
Delta is less than zero, so there is no solution for the equation

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