20+8=4(4x-3)

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Solution for 20+8=4(4x-3) equation: 



20+8=4(4x-3)

We move all terms to the left:

20+8-(4(4x-3))=0

We add all the numbers together, and all the variables

-(4(4x-3))+28=0



We calculate terms in parentheses: -(4(4x-3)), so:

4(4x-3)

We multiply parentheses

16x-12

Back to the equation:

-(16x-12)



We get rid of parentheses

-16x+12+28=0

We add all the numbers together, and all the variables

-16x+40=0

We move all terms containing x to the left, all other terms to the right

-16x=-40

x=-40/-16

x=2+1/2

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