20+x=5(1/5x+2)

Solution for 20+x=5(1/5x+2) equation:

20+x=5(1/5x+2)

We move all terms to the left:

20+x-(5(1/5x+2))=0


Domain of the equation: 5x+2))!=0

x∈R


We multiply all the terms by the denominator


x*5x+20*5x+2))-(5(1+2))=0

We add all the numbers together, and all the variables

x*5x+20*5x+2))-(53)=0

We add all the numbers together, and all the variables

x*5x+20*5x=0

Wy multiply elements

5x^2+100x=0

a = 5; b = 100; c = 0;
Δ = b2-4ac
Δ = 1002-4·5·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-100}{2*5}=\frac{-200}{10}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+100}{2*5}=\frac{0}{10}
=0
$