20+z+10+180-(3z-16)=180

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Solution for 20+z+10+180-(3z-16)=180 equation: 



20+z+10+180-(3z-16)=180

We move all terms to the left:

20+z+10+180-(3z-16)-(180)=0

We add all the numbers together, and all the variables

z-(3z-16)+30=0

We get rid of parentheses

z-3z+16+30=0

We add all the numbers together, and all the variables

-2z+46=0

We move all terms containing z to the left, all other terms to the right

-2z=-46

z=-46/-2

z=+23

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