20-(-2-10x)+50=102

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Solution for 20-(-2-10x)+50=102 equation: 



20-(-2-10x)+50=102

We move all terms to the left:

20-(-2-10x)+50-(102)=0

We add all the numbers together, and all the variables

-(-10x-2)+20+50-102=0

We add all the numbers together, and all the variables

-(-10x-2)-32=0

We get rid of parentheses

10x+2-32=0

We add all the numbers together, and all the variables

10x-30=0

We move all terms containing x to the left, all other terms to the right

10x=30

x=30/10

x=3

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