20-(1/5)d=(3/10)d+16

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Solution for 20-(1/5)d=(3/10)d+16 equation:



20-(1/5)d=(3/10)d+16
We move all terms to the left:
20-(1/5)d-((3/10)d+16)=0
Domain of the equation: 5)d!=0
d!=0/1
d!=0
d∈R
Domain of the equation: 10)d+16)!=0
d!=0/1
d!=0
d∈R
We add all the numbers together, and all the variables
-(+1/5)d-((+3/10)d+16)+20=0
We multiply parentheses
-d^2-((+3/10)d+16)+20=0
We multiply all the terms by the denominator
-d^2*10)d+16)-((+20*10)d+16)+3=0
We add all the numbers together, and all the variables
-d^2*10)d+16)-(200d+16)+3=0
Wy multiply elements
-10d^3=0
We do not support edpression: d^3

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