20-(2c+4)=2(c+3)+3

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Solution for 20-(2c+4)=2(c+3)+3 equation: 



20-(2c+4)=2(c+3)+3

We move all terms to the left:

20-(2c+4)-(2(c+3)+3)=0

We get rid of parentheses

-2c-(2(c+3)+3)-4+20=0



We calculate terms in parentheses: -(2(c+3)+3), so:

2(c+3)+3

We multiply parentheses

2c+6+3

We add all the numbers together, and all the variables

2c+9

Back to the equation:

-(2c+9)



We add all the numbers together, and all the variables

-2c-(2c+9)+16=0

We get rid of parentheses

-2c-2c-9+16=0

We add all the numbers together, and all the variables

-4c+7=0

We move all terms containing c to the left, all other terms to the right

-4c=-7

c=-7/-4

c=1+3/4

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