20-(2c+4)=c+3+c

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Solution for 20-(2c+4)=c+3+c equation: 



20-(2c+4)=c+3+c

We move all terms to the left:

20-(2c+4)-(c+3+c)=0

We add all the numbers together, and all the variables

-(2c+4)-(2c+3)+20=0

We get rid of parentheses

-2c-2c-4-3+20=0

We add all the numbers together, and all the variables

-4c+13=0

We move all terms containing c to the left, all other terms to the right

-4c=-13

c=-13/-4

c=3+1/4

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