20-(2u+12)=2

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Solution for 20-(2u+12)=2 equation: 



20-(2u+12)=2

We move all terms to the left:

20-(2u+12)-(2)=0

We add all the numbers together, and all the variables

-(2u+12)+18=0

We get rid of parentheses

-2u-12+18=0

We add all the numbers together, and all the variables

-2u+6=0

We move all terms containing u to the left, all other terms to the right

-2u=-6

u=-6/-2

u=+3

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