20-(3x-3)=22+(5x-3)

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Solution for 20-(3x-3)=22+(5x-3) equation: 



20-(3x-3)=22+(5x-3)

We move all terms to the left:

20-(3x-3)-(22+(5x-3))=0

We get rid of parentheses

-3x-(22+(5x-3))+3+20=0



We calculate terms in parentheses: -(22+(5x-3)), so:

22+(5x-3)

determiningTheFunctionDomain
(5x-3)+22

We get rid of parentheses

5x-3+22

We add all the numbers together, and all the variables

5x+19

Back to the equation:

-(5x+19)



We add all the numbers together, and all the variables

-3x-(5x+19)+23=0

We get rid of parentheses

-3x-5x-19+23=0

We add all the numbers together, and all the variables

-8x+4=0

We move all terms containing x to the left, all other terms to the right

-8x=-4

x=-4/-8

x=1/2

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