20-(4x-5)=5(x-3)-5

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Solution for 20-(4x-5)=5(x-3)-5 equation: 



20-(4x-5)=5(x-3)-5

We move all terms to the left:

20-(4x-5)-(5(x-3)-5)=0

We get rid of parentheses

-4x-(5(x-3)-5)+5+20=0



We calculate terms in parentheses: -(5(x-3)-5), so:

5(x-3)-5

We multiply parentheses

5x-15-5

We add all the numbers together, and all the variables

5x-20

Back to the equation:

-(5x-20)



We add all the numbers together, and all the variables

-4x-(5x-20)+25=0

We get rid of parentheses

-4x-5x+20+25=0

We add all the numbers together, and all the variables

-9x+45=0

We move all terms containing x to the left, all other terms to the right

-9x=-45

x=-45/-9

x=+5

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