20-(7+4)=n/3+5

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Solution for 20-(7+4)=n/3+5 equation: 



20-(7+4)=n/3+5

We move all terms to the left:

20-(7+4)-(n/3+5)=0

We add all the numbers together, and all the variables

-(n/3+5)+20-11=0

We add all the numbers together, and all the variables

-(n/3+5)+9=0

We get rid of parentheses

-n/3-5+9=0

We multiply all the terms by the denominator


-n-5*3+9*3=0

We add all the numbers together, and all the variables

-1n+12=0

We move all terms containing n to the left, all other terms to the right

-n=-12

n=-12/-1

n=+12

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