20-(8+x)=39-(1-x)

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Solution for 20-(8+x)=39-(1-x) equation: 



20-(8+x)=39-(1-x)

We move all terms to the left:

20-(8+x)-(39-(1-x))=0

We add all the numbers together, and all the variables

-(x+8)-(39-(-1x+1))+20=0

We get rid of parentheses

-x-(39-(-1x+1))-8+20=0



We calculate terms in parentheses: -(39-(-1x+1)), so:

39-(-1x+1)

determiningTheFunctionDomain
-(-1x+1)+39

We get rid of parentheses

1x-1+39

We add all the numbers together, and all the variables

x+38

Back to the equation:

-(x+38)



We add all the numbers together, and all the variables

-1x-(x+38)+12=0

We get rid of parentheses

-1x-x-38+12=0

We add all the numbers together, and all the variables

-2x-26=0

We move all terms containing x to the left, all other terms to the right

-2x=26

x=26/-2

x=-13

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