20-(x+1)=7(x-3)

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Solution for 20-(x+1)=7(x-3) equation:



20-(x+1)=7(x-3)
We move all terms to the left:
20-(x+1)-(7(x-3))=0
We get rid of parentheses
-x-(7(x-3))-1+20=0
We calculate terms in parentheses: -(7(x-3)), so:
7(x-3)
We multiply parentheses
7x-21
Back to the equation:
-(7x-21)
We add all the numbers together, and all the variables
-1x-(7x-21)+19=0
We get rid of parentheses
-1x-7x+21+19=0
We add all the numbers together, and all the variables
-8x+40=0
We move all terms containing x to the left, all other terms to the right
-8x=-40
x=-40/-8
x=+5

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