20-(x+5)=3(x-3)

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Solution for 20-(x+5)=3(x-3) equation: 



20-(x+5)=3(x-3)

We move all terms to the left:

20-(x+5)-(3(x-3))=0

We get rid of parentheses

-x-(3(x-3))-5+20=0



We calculate terms in parentheses: -(3(x-3)), so:

3(x-3)

We multiply parentheses

3x-9

Back to the equation:

-(3x-9)



We add all the numbers together, and all the variables

-1x-(3x-9)+15=0

We get rid of parentheses

-1x-3x+9+15=0

We add all the numbers together, and all the variables

-4x+24=0

We move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4

x=+6

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