20-(x/4)=12

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Solution for 20-(x/4)=12 equation:



20-(x/4)=12
We move all terms to the left:
20-(x/4)-(12)=0
We add all the numbers together, and all the variables
-(+x/4)+20-12=0
We add all the numbers together, and all the variables
-(+x/4)+8=0
We get rid of parentheses
-x/4+8=0
We multiply all the terms by the denominator
-x+8*4=0
We add all the numbers together, and all the variables
-1x+32=0
We move all terms containing x to the left, all other terms to the right
-x=-32
x=-32/-1
x=+32

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