20-(z/3)=(z/2)

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Solution for 20-(z/3)=(z/2) equation:


z in (-oo:+oo)

20-(z/3) = z/2 // - z/2

20-(z/3)-(z/2) = 0

20-5/6*z = 0 // - 20

-5/6*z = -20 // : -5/6

z = -20/(-5/6)

z = 24

z = 24

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