20-1/5d=3/10d=3/10d+16

Solution for 20-1/5d=3/10d=3/10d+16 equation:

20-1/5d=3/10d=3/10d+16

We move all terms to the left:

20-1/5d-(3/10d)=0


Domain of the equation: 5d!=0

d!=0/5

d!=0

d∈R



Domain of the equation: 10d)!=0

d!=0/1

d!=0

d∈R


We add all the numbers together, and all the variables

-1/5d-(+3/10d)+20=0

We get rid of parentheses

-1/5d-3/10d+20=0

We calculate fractions


(-10d)/50d^2+(-15d)/50d^2+20=0

We multiply all the terms by the denominator


(-10d)+(-15d)+20*50d^2=0

Wy multiply elements

1000d^2+(-10d)+(-15d)=0

We get rid of parentheses

1000d^2-10d-15d=0

We add all the numbers together, and all the variables

1000d^2-25d=0

a = 1000; b = -25; c = 0;
Δ = b2-4ac
Δ = -252-4·1000·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-25}{2*1000}=\frac{0}{2000}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+25}{2*1000}=\frac{50}{2000}
=1/40
$