20-12i=20+3(4i)

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Solution for 20-12i=20+3(4i) equation: 



20-12i=20+3(4i)

We move all terms to the left:

20-12i-(20+3(4i))=0

We add all the numbers together, and all the variables

-12i-(34i+20)+20=0

We get rid of parentheses

-12i-34i-20+20=0

We add all the numbers together, and all the variables

-46i=0

i=0/-46

i=0

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