20-12z=-19+3-16z

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Solution for 20-12z=-19+3-16z equation: 



20-12z=-19+3-16z

We move all terms to the left:

20-12z-(-19+3-16z)=0

We add all the numbers together, and all the variables

-12z-(-16z-16)+20=0

We get rid of parentheses

-12z+16z+16+20=0

We add all the numbers together, and all the variables

4z+36=0

We move all terms containing z to the left, all other terms to the right

4z=-36

z=-36/4

z=-9

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