20-2(x+1)=-4(3-x)

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Solution for 20-2(x+1)=-4(3-x) equation: 



20-2(x+1)=-4(3-x)

We move all terms to the left:

20-2(x+1)-(-4(3-x))=0

We add all the numbers together, and all the variables

-2(x+1)-(-4(-1x+3))+20=0

We multiply parentheses

-2x-(-4(-1x+3))-2+20=0



We calculate terms in parentheses: -(-4(-1x+3)), so:

-4(-1x+3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

-2x-(4x-12)+18=0

We get rid of parentheses

-2x-4x+12+18=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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