20-2(x+5)=22

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Solution for 20-2(x+5)=22 equation: 



20-2(x+5)=22

We move all terms to the left:

20-2(x+5)-(22)=0

We add all the numbers together, and all the variables

-2(x+5)-2=0

We multiply parentheses

-2x-10-2=0

We add all the numbers together, and all the variables

-2x-12=0

We move all terms containing x to the left, all other terms to the right

-2x=12

x=12/-2

x=-6

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