20-2/10d=3/10d+16

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Solution for 20-2/10d=3/10d+16 equation: 


d in (-oo:+oo)

20-((2/10)*d) = (3/10)*d+16 // - (3/10)*d+16

20-((2/10)*d)-((3/10)*d)-16 = 0

(-1/5)*d+(-3/10)*d-16+20 = 0

4-1/2*d = 0 // - 4

-1/2*d = -4 // : -1/2

d = -4/(-1/2)

d = 8

d = 8

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