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20-2x=1/2x
We move all terms to the left:
20-2x-(1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-2x-(+1/2x)+20=0
We get rid of parentheses
-2x-1/2x+20=0
We multiply all the terms by the denominator
-2x*2x+20*2x-1=0
Wy multiply elements
-4x^2+40x-1=0
a = -4; b = 40; c = -1;
Δ = b2-4ac
Δ = 402-4·(-4)·(-1)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-12\sqrt{11}}{2*-4}=\frac{-40-12\sqrt{11}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+12\sqrt{11}}{2*-4}=\frac{-40+12\sqrt{11}}{-8} $
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