20-3(x-2)=27-6x+2(2x-1)

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Solution for 20-3(x-2)=27-6x+2(2x-1) equation: 



20-3(x-2)=27-6x+2(2x-1)

We move all terms to the left:

20-3(x-2)-(27-6x+2(2x-1))=0

We multiply parentheses

-3x-(27-6x+2(2x-1))+6+20=0



We calculate terms in parentheses: -(27-6x+2(2x-1)), so:

27-6x+2(2x-1)

determiningTheFunctionDomain
-6x+2(2x-1)+27

We multiply parentheses

-6x+4x-2+27

We add all the numbers together, and all the variables

-2x+25

Back to the equation:

-(-2x+25)



We add all the numbers together, and all the variables

-3x-(-2x+25)+26=0

We get rid of parentheses

-3x+2x-25+26=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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