20-3x=-4(4x+2)-4(-5-3x)

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Solution for 20-3x=-4(4x+2)-4(-5-3x) equation: 



20-3x=-4(4x+2)-4(-5-3x)

We move all terms to the left:

20-3x-(-4(4x+2)-4(-5-3x))=0

We add all the numbers together, and all the variables

-3x-(-4(4x+2)-4(-3x-5))+20=0



We calculate terms in parentheses: -(-4(4x+2)-4(-3x-5)), so:

-4(4x+2)-4(-3x-5)

We multiply parentheses

-16x+12x-8+20

We add all the numbers together, and all the variables

-4x+12

Back to the equation:

-(-4x+12)



We get rid of parentheses

-3x+4x-12+20=0

We add all the numbers together, and all the variables

x+8=0

We move all terms containing x to the left, all other terms to the right

x=-8

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