20-3y/5=y-12

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Solution for 20-3y/5=y-12 equation: 


y in (-oo:+oo)

20-((3*y)/5) = y-12 // - y-12

12-((3*y)/5)-y+20 = 0

(-3/5)*y-y+12+20 = 0

32-8/5*y = 0 // - 32

-8/5*y = -32 // : -8/5

y = -32/(-8/5)

y = 20

y = 20

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