20-4(2x+1)=8x-4(8+x)

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Solution for 20-4(2x+1)=8x-4(8+x) equation: 



20-4(2x+1)=8x-4(8+x)

We move all terms to the left:

20-4(2x+1)-(8x-4(8+x))=0

We add all the numbers together, and all the variables

-4(2x+1)-(8x-4(x+8))+20=0

We multiply parentheses

-8x-(8x-4(x+8))-4+20=0



We calculate terms in parentheses: -(8x-4(x+8)), so:

8x-4(x+8)

We multiply parentheses

8x-4x-32

We add all the numbers together, and all the variables

4x-32

Back to the equation:

-(4x-32)



We add all the numbers together, and all the variables

-8x-(4x-32)+16=0

We get rid of parentheses

-8x-4x+32+16=0

We add all the numbers together, and all the variables

-12x+48=0

We move all terms containing x to the left, all other terms to the right

-12x=-48

x=-48/-12

x=+4

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