20-4(2x-3)=3(x+5)

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Solution for 20-4(2x-3)=3(x+5) equation: 



20-4(2x-3)=3(x+5)

We move all terms to the left:

20-4(2x-3)-(3(x+5))=0

We multiply parentheses

-8x-(3(x+5))+12+20=0



We calculate terms in parentheses: -(3(x+5)), so:

3(x+5)

We multiply parentheses

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

-8x-(3x+15)+32=0

We get rid of parentheses

-8x-3x-15+32=0

We add all the numbers together, and all the variables

-11x+17=0

We move all terms containing x to the left, all other terms to the right

-11x=-17

x=-17/-11

x=1+6/11

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