20-4(3x-5)+2x=5(x-7)

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Solution for 20-4(3x-5)+2x=5(x-7) equation: 



20-4(3x-5)+2x=5(x-7)

We move all terms to the left:

20-4(3x-5)+2x-(5(x-7))=0

We add all the numbers together, and all the variables

2x-4(3x-5)-(5(x-7))+20=0

We multiply parentheses

2x-12x-(5(x-7))+20+20=0



We calculate terms in parentheses: -(5(x-7)), so:

5(x-7)

We multiply parentheses

5x-35

Back to the equation:

-(5x-35)



We add all the numbers together, and all the variables

-10x-(5x-35)+40=0

We get rid of parentheses

-10x-5x+35+40=0

We add all the numbers together, and all the variables

-15x+75=0

We move all terms containing x to the left, all other terms to the right

-15x=-75

x=-75/-15

x=+5

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