20-41=3(x-2)-6

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Solution for 20-41=3(x-2)-6 equation: 



20-41=3(x-2)-6

We move all terms to the left:

20-41-(3(x-2)-6)=0

We add all the numbers together, and all the variables

-(3(x-2)-6)-21=0



We calculate terms in parentheses: -(3(x-2)-6), so:

3(x-2)-6

We multiply parentheses

3x-6-6

We add all the numbers together, and all the variables

3x-12

Back to the equation:

-(3x-12)



We get rid of parentheses

-3x+12-21=0

We add all the numbers together, and all the variables

-3x-9=0

We move all terms containing x to the left, all other terms to the right

-3x=9

x=9/-3

x=-3

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