20-4x=10-9(4-x)-(3x-6)

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Solution for 20-4x=10-9(4-x)-(3x-6) equation: 



20-4x=10-9(4-x)-(3x-6)

We move all terms to the left:

20-4x-(10-9(4-x)-(3x-6))=0

We add all the numbers together, and all the variables

-4x-(10-9(-1x+4)-(3x-6))+20=0



We calculate terms in parentheses: -(10-9(-1x+4)-(3x-6)), so:

10-9(-1x+4)-(3x-6)

determiningTheFunctionDomain
-9(-1x+4)-(3x-6)+10

We multiply parentheses

9x-(3x-6)-36+10

We get rid of parentheses

9x-3x+6-36+10

We add all the numbers together, and all the variables

6x-20

Back to the equation:

-(6x-20)



We get rid of parentheses

-4x-6x+20+20=0

We add all the numbers together, and all the variables

-10x+40=0

We move all terms containing x to the left, all other terms to the right

-10x=-40

x=-40/-10

x=+4

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