20-4x=40-12x

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Solution for 20-4x=40-12x equation: 



20-4x=40-12x

We move all terms to the left:

20-4x-(40-12x)=0

We add all the numbers together, and all the variables

-4x-(-12x+40)+20=0

We get rid of parentheses

-4x+12x-40+20=0

We add all the numbers together, and all the variables

8x-20=0

We move all terms containing x to the left, all other terms to the right

8x=20

x=20/8

x=2+1/2

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