20-5(x-2)=2(x+3)-3(7-x)-4

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Solution for 20-5(x-2)=2(x+3)-3(7-x)-4 equation: 



20-5(x-2)=2(x+3)-3(7-x)-4

We move all terms to the left:

20-5(x-2)-(2(x+3)-3(7-x)-4)=0

We add all the numbers together, and all the variables

-5(x-2)-(2(x+3)-3(-1x+7)-4)+20=0

We multiply parentheses

-5x-(2(x+3)-3(-1x+7)-4)+10+20=0



We calculate terms in parentheses: -(2(x+3)-3(-1x+7)-4), so:

2(x+3)-3(-1x+7)-4

We multiply parentheses

2x+3x+6-21-4

We add all the numbers together, and all the variables

5x-19

Back to the equation:

-(5x-19)



We add all the numbers together, and all the variables

-5x-(5x-19)+30=0

We get rid of parentheses

-5x-5x+19+30=0

We add all the numbers together, and all the variables

-10x+49=0

We move all terms containing x to the left, all other terms to the right

-10x=-49

x=-49/-10

x=4+9/10

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