20-5n=n+22(n+2)=20

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Solution for 20-5n=n+22(n+2)=20 equation: 



20-5n=n+22(n+2)=20

We move all terms to the left:

20-5n-(n+22(n+2))=0



We calculate terms in parentheses: -(n+22(n+2)), so:

n+22(n+2)

We multiply parentheses

n+22n+44

We add all the numbers together, and all the variables

23n+44

Back to the equation:

-(23n+44)



We get rid of parentheses

-5n-23n-44+20=0

We add all the numbers together, and all the variables

-28n-24=0

We move all terms containing n to the left, all other terms to the right

-28n=24

n=24/-28

n=-6/7

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