20-x=35x2

Solution for 20-x=35x2 equation:

20-x=35x^2

We move all terms to the left:

20-x-(35x^2)=0

determiningTheFunctionDomain
-35x^2-x+20=0

We add all the numbers together, and all the variables

-35x^2-1x+20=0

a = -35; b = -1; c = +20;
Δ = b2-4ac
Δ = -12-4·(-35)·20
Δ = 2801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{2801}}{2*-35}=\frac{1-\sqrt{2801}}{-70}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{2801}}{2*-35}=\frac{1+\sqrt{2801}}{-70}
$