20-x=35x2-x

Solution for 20-x=35x2-x equation:

20-x=35x^2-x

We move all terms to the left:

20-x-(35x^2-x)=0

We add all the numbers together, and all the variables

-1x-(35x^2-x)+20=0

We get rid of parentheses

-35x^2-1x+x+20=0

We add all the numbers together, and all the variables

-35x^2+20=0

a = -35; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·(-35)·20
Δ = 2800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2800}=\sqrt{400*7}=\sqrt{400}*\sqrt{7}=20\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{7}}{2*-35}=\frac{0-20\sqrt{7}}{-70}
=-\frac{20\sqrt{7}}{-70}
=-\frac{2\sqrt{7}}{-7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{7}}{2*-35}=\frac{0+20\sqrt{7}}{-70}
=\frac{20\sqrt{7}}{-70}
=\frac{2\sqrt{7}}{-7}
$