If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12/25
(3*7-(3*3^2))/(3^2-6)
ln(x/4+1)
1*x^4+3*x^2+4*x+0*x^3+0 = 0;x
x
1*x^3+3*x+0*x^2+4 = 0;x
x
| v=1/3B*h | | 51+-1y=760.5+-1y | | n-4/-10=-1 | | 72r^2+35r+3= | | (7-9(ln(x)))/((x)^(2))=0 | | -2+x=16 | | X^2+3x-4=67 | | f(-5)=5x+13 | | (7-9(ln(x)))/((x)^(2)) | | 17-x=68 | | 63=5/8x | | 1/3-2/3R=1 | | X-6+7h=42 | | 52+46+x=180 | | x+(5x+46)=14 | | 11t-6t=10 | | 4w+w-2w+2=11 | | 2(3-(4-x)-3x)=4 | | X+6+52=90 | | 5.2t=36.4 | | -4x-28= | | -11b-4b=-15 | | -(4x-14)+4(4x+7)= | | 3(x+1)+2x=18 | | x^2-126x+1296=0 | | 5+12x+8=24-6x+2-x | | 18r-6r-11r=15 | | 40=54 | | 4x+3=2x-29 | | 2x+2y=1521 | | 27-6x=17+4x | | 8Xsquared+26X+15=0 |