20/(4x-4)+(1/4)=5/(x-1)

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Solution for 20/(4x-4)+(1/4)=5/(x-1) equation: 



20/(4x-4)+(1/4)=5/(x-1)

We move all terms to the left:

20/(4x-4)+(1/4)-(5/(x-1))=0



Domain of the equation: (4x-4)!=0

We move all terms containing x to the left, all other terms to the right

4x!=4

x!=4/4

x!=1

x∈R





Domain of the equation: (x-1))!=0

x∈R



We add all the numbers together, and all the variables

20/(4x-4)-(5/(x-1))+(+1/4)=0

We get rid of parentheses

20/(4x-4)-(5/(x-1))+1/4=0

We calculate fractions


80x/((4x-4)*(x-1))*4)+(-(5*(4x-4)*4)/((4x-4)*(x-1))*4)+(1*(4x-4)*(x-1)))/((4x-4)*(x-1))*4)=0

We can not solve this equation

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