20/12=40/t

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Solution for 20/12=40/t equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

20/12 = 40/t // - 40/t

20/12-(40/t) = 0

20/12-40*t^-1 = 0

-40*t^-1 = -5/3 // : -40

t^-1 = 1/24

-1 < 0

1/(t^1) = 1/24 // * t^1

1 = 1/24*t^1 // : 1/24

24 = t^1

t = 24

t = 24

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