20/18=50/t

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Solution for 20/18=50/t equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

20/18 = 50/t // - 50/t

20/18-(50/t) = 0

20/18-50*t^-1 = 0

-50*t^-1 = -10/9 // : -50

t^-1 = 1/45

-1 < 0

1/(t^1) = 1/45 // * t^1

1 = 1/45*t^1 // : 1/45

45 = t^1

t = 45

t = 45

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