20/2x=10/x+2

Solution for 20/2x=10/x+2 equation:

20/2x=10/x+2

We move all terms to the left:

20/2x-(10/x+2)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: x+2)!=0

x∈R


We get rid of parentheses

20/2x-10/x-2=0

We calculate fractions


20x/2x^2+(-20x)/2x^2-2=0

We multiply all the terms by the denominator


20x+(-20x)-2*2x^2=0

Wy multiply elements

-4x^2+20x+(-20x)=0

We get rid of parentheses

-4x^2+20x-20x=0

We add all the numbers together, and all the variables

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$